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6x^2=3x+30.
We move all terms to the left:
6x^2-(3x+30.)=0
We add all the numbers together, and all the variables
6x^2-(3x+30)=0
We get rid of parentheses
6x^2-3x-30=0
a = 6; b = -3; c = -30;
Δ = b2-4ac
Δ = -32-4·6·(-30)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*6}=\frac{30}{12} =2+1/2 $
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